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25x^2+625x-2=0
a = 25; b = 625; c = -2;
Δ = b2-4ac
Δ = 6252-4·25·(-2)
Δ = 390825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{390825}=\sqrt{2025*193}=\sqrt{2025}*\sqrt{193}=45\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(625)-45\sqrt{193}}{2*25}=\frac{-625-45\sqrt{193}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(625)+45\sqrt{193}}{2*25}=\frac{-625+45\sqrt{193}}{50} $
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